How do you pronounce bicubic in English (1 out of 27).

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Translation of bicubic

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IPA (International Phonetic Alphabet) of bicubic

The International Phonetic Alphabet (IPA) is an alphabetic system of phonetic notation based primarily on the Latin alphabet. With phonetic transcriptions, dictionarie tell you about the pronunciation of words, because the spelling of an English word does not tell you how you should pronounce it. Below is the phonetic transcription of bicubic:
/bɪkjubɪk/

bicubic on Youtube

  1. interpolating 4 points or I have a bicubic patch, bicubic Hermite patch which is defined
  2. interpolation, for cubic interpolation, it will be called a bicubic interpolation.
  3. pixel value at this particular image and the same concept can also be extended for bicubic
  4. bicubic interpolation where you have to do interpoltion both along the rows and after
  5. So if you have a 4 into 4 bicubic Bezier surface in matrix form this is what you will get.
  6. here which you have, the bicubic because there are two of those and these are your Bijs the
  7. So, if you want to fit a 4 into 4 bicubic Bezier surface using a matrix equation you
  8. in which you want since it is bicubic it is cubic nature and you just put this 16 elements
  9. It may not always be the case that you need to fit a bicubic curve only over 4 into 4
  10. 4 or it could be 4 into 5. So what do you do, you may need to fit a bicubic Bezier surface
  11. 4 into 4 bicubic Bezier surface in matrix form and if you look at this 5 into 3 a non
  12. discussed about the bicubic 4 into 4 or a 5 into 3 depending upon the direction U and
  13. 4 bicubic Bezier surface in a matrix form 16 points are given and this is the matrix
  14. square 5 into 3 but you want it will fit a 4 into 4 bicubic Bezier surface then on one
  15. or a nurbs curve to define like a bicubic patch or let's say a Bezier patch or a B-spline
  16. we talked about the Bezier surfaces. So as an example here what you see is a bicubic
  17. It is a bicubic patch because it is cubic in both u and v. And in fact the construction
  18. trying to look at a bicubic surface which would satisfy certain boundary condition. And just by extending the matrix formulation
  19. I can construct a hermite bicubic surface where these F primes are very similar to the
  20. So, given this geometric information I can then construct the bicubic hermite surface.