Practice English Speaking&Listening with: Lecture-41-Transmission Lines

Difficulty: 0

In this lecture, I want to take a look back at what we have done. And then make the final

step from what we have been doing as wave theory to something more practical which is

the subjects of the transmission lines. Now, let us look at where we started we started

with statics.

And we concluded that there where 2 equations which governed electric field 1 was curl of

E was equal to 0. And the other was divergence of D was equal to row, because curl of E was

equal to 0 this allowed as to say the electric field is derived from a potential. So, E was

equal to minus grade pi. And we invented this concept of the displacement vector, because

the any material has charges init which are bound to where they are to the atoms in which

they belong. But in the presence of the electric field does not introduced polarization, and

we work it out in this course that you can show that D is equal to epsilon E that is

D is proportional to E. So, the correct equation here is divergence

of E is equal to row total over epsilon naught, but by introducing the concept of induced

electric field. And saying that the induced electric field is proportional to the electric

field itself we could write this as divergence of E is equal to row bound plus row free divided

by epsilon naught. And we identified this row bound by epsilon naught this piece with

the divergence of E induced. So, and you came up with the new equation which was divergence

of epsilon naught times E minus E induced was equal to row free and that is this equation.

So, this is nothing but D, so this was statics and the final achievement of statics was the

poison equation which gave us that del squared pi was equal to minus row over epsilon naught.

Now, that is something that I did not do here, because they were purely mathematical in nature.

One of them was that you can prove that if you have any volume V and if on the surface

of this volume on either any point specified either pi or del pi del n. Then the solution

inside exist and is unique, so that means that this equation has is well defined and

has unique solutions. So, that was statics that is electrostatics when you went to magneto

statics and when you went to magneto statics the picture was exactly reversed.

We found that we could write curl of B was equal to mu not j and we could write divergence

of B was equal to 0 now, I discussed with you that the magnetic field is not a new field.

In fact, if you go back and look through some of my older lectures the magnetic field is

nothing more than the electric field when you apply the electivity to it. So, it is

actually a side effect of the electric field. Now, you take this equation and once again

apply it to materials this equations becomes mu not j bound plus mu not j free. And once

again you can attach and implied field to this bound charge current. And you say that

this is equal to curl of B induced which allowed as to say curl of B minus B

induced divided by mu not was equal to j free. And we identified this as a new vector which

we called H. So, we had 4 equations 1 was curl of E was 0 divergence of D was row curl

of H is j divergence of D was 0. And these 4 equations took care of time independent

phenomena. However, once you went to time dependent phenomena

2 of this, equations where found inadequate. So, we added extra terms first this curl equations

turned out to have a correction to it which was minus del D del t. And the effect of minus

del B del t could be seen, because if this equation was still correct which meant B was

the curl of some other function A substituting if back in here you found that E was minus

grade pi. But substituting this curl back into this you also got the minus del A del

t. So, the electric field was not only due to a gradient of potential it was also due

to a time dependence of the vector potential. Similarly, this equation was found to be unsatisfactory

you found you needed a new term which was del D del t. So, that gave us the final system

of equations and let me write them down once.

So, that we can see that curl of E is equal to minus del B del t faradays law divergence

D is equal to the free charge gausses law divergence of B is 0. There is no such thing

as magnetic charge curl of H is equal to the free charge plus del D del t. That is what

we call Maxwells equation D is equal to epsilon E where epsilon is the permittivity

B is equal to mu H where mu is the permeability. And we have one more equations which connects

row and j which is divergence of j is equal to minus del row del t. So, these are the

equation, that define the field and there is one equation. That is coming outside the

system which happens to be at least as important as these which is the force equation the force

on any charged particle is q E plus V cross B.

So, these are the system of equations that we have been looking at through this whole

course initially. We ignored the time derivatives and we did statics then we took that time

derivatives into account. We got faradays law induced dmf motional emf. And then finally,

we got waves we have spent quite some waves. Now, and what I want to do is to make those

wave solutions interesting to someone was not going to be in communication theory, because

really. If you are not going to do am and fm transmission why should you learn about

the wave theory? Well, there is good reason for that that why you should learn. And it

has to do with the fact that even if you do not do free space wave propagation every electrical

engineer like it or not is going to have to deal with the transmission lines.

So, what is the transmission line? Up to now we have looked at waves which travel in 1

dimension. Basically we know that there are more complicated solutions, but we have looked

only at 1 dimensional solutions you have the electric field in some direction magnetic

field 90 degrees to it. And E cross H is the direction in which the wave is traveling.

Now, the first things of interest versus that if you had a torch

and you shown light from this torch you know that. The light spreads what; that means,

is if you standing some where you shine a torch at the wall. The spot will appear on

the wall if you shine the same torch at a far away building this part will be much bigger.

And if you shine it at a mountain you won it see anything at all.

So, what it means is that this beam is spreading out and we work this out in terms of pointing

theorem. We said that does not inverse square law for intensity namely volume integral of

E cross H dot ds is constant assuming. That your light bulb is in 1 place you are asking

how much how spread out is my electric. And magnetic field of my wave what you have is

E cross H dot ds is independent of how far away I measure it if I measure using a surface

like this. I will get 1 answer if I measure using a surface like this. I will get the

same answer let, because the same wave is going through there are no sources here. So,

I should get what ever came in must leave E cross H is power power density.

If you like we saw last time it has units of watts per meter square. So, this power

density is inversely proportional to the area of the surface and the area of this sphere

is proportional to the square of the radius. So, power density is proportional to 1 over

r squared that explains a lot of thing. It explains the suns why the sun is not brighter,

than it is how lights spreads out it explains the great number of things. But it is an inconvenience

supposing I want information to travel from point a to point b without spreading out.

Well of course, I can design very good optics and make sure that the light does not diverge.

And we do that when you have point to point micro wave links are transmitter has 1 volt

of power and links may be tones of kilometers apart. So, it is possible to have very low

powered sources going through air without spreading much; however, that is not always

the best approach. So, what we prefer to do is to have cables we will prefer to take this

waves packaged it in to a cable and send it to from point a to point b like.

. We have a computer and we have a cable an

Ethernet cable and it connect to a hub. This cable is also taking time dependent information

100 millions bits per second from this point to this point. And the wave that is traveling

through this cable is force to stay inside the cable and. So, does not obeys the inverse

square law that is the strength of the wave at this point is not inversely proportional

to the distance it attenuate. There are losses in this cable, but otherwise if it where loss

less the amount of energy here would be equal to the amount of energy there left here. So,

what we really want is that same wave that travels through the space except we want to

bottle it into a pipe. We like to look at what solution at one can have if I take a

wave and I make it travel inside a metallic pipe unfortunately. There is a bad news lets

look at this along the axis, so its got some shape this is x this is y.

So, this pipe has some cross section now my electric field. And my magnetic field are

what they are, so let say I have my electric field this way. And my magnetic field is this

way now you can see that there are places where the electric field will be tangential

to the wall. Now, you have already discuss that tangential electric field is always continues

since is always continues. The electric field inside the metal is also what it at the wall

which means you have a very strong electric field inside the conducting material. Similarly,

if you look at this point your magnetic field has a normal components and just as we show

as the tangential components of the electric field is always continues. The tangential

the normal component of magnetic field is also always continues.

So, you find that what ever the magnetic field is here is also inside the material. But you

know that amperes law tells us that if you have an electric field you have current if

you have a magnetic field you have an induced electric field. And therefore, you have again

lots of current. So, if your current conductivity your sigma is extremely high you cannot really

afford to have a large electric field which means that this kind of solution is not possible,

if you try to package what is called a plane wave. The kind of wave we will be looking

at and put it into a pipe the plane wave will be destroyed in centimeters it will just not

survive. If a plane wave is to survive it must change

it must be a different kind of a wave it must actually vary not only in z. But it must also

vary in x and in y and how much did vary it must vary by becoming 0 wherever the electric

field tries to be tangential. And the magnetic field must become 0 wherever it is trying

to be normal. There are such solutions and the study of waves flowing through pipes.

So, it is a very important subject its called wave guide theory for instance if you are

doing radar. And you have building wave you have generated your strong radio frequency

signal. And you have your rador antennae well there will be 100 meters are few 100 meters

between the antennae. And the place where generating the signal, so this high frequency

signal has to be taken there. And it may be 10 kilowatts of power that must be given to

this, antennae it has to go through a pipe. And such wave that go through a pipe and driven

rador antennae these are waveguide. But I does the problem with the waveguide problems

with waves flowing in pipes is that your electric field. And your magnetic field, are not the

simple fields that we have looked at so far there are more complicated fields for instance

if you had the cross section that was rectangular. So, you had x you had y then you could imagine

that you would have an electric field that was 0 at the 2 ends. And slowly becomes bigger

biggest and become smaller such a solution is quite possible. And these kinds of solutions

exist and they are called transverse electric. And transverse magnetic modes you will see

the names TE and TM modes that is all, its means. It means that there is variation in

x and y direction, but transverse electric mode is 1 which does not have any electric

field in the z direction. The transverse magnetic mode is the mode that does not have any magnetic

field in the z direction unlike all, this mode which have quite complicated. And not

really of importance to low frequency application there is one special mode. And this special

mode can travel at low frequencies it can travel through pipes. And it looks like a

plane wave and it that wave I want to talk about today.

Let us go back to the wave equation, so we had Del squared E minus 1 over C squared del

square E del t squared is equal to 0. Now, I am going to write this Del squared as 2

parts its actually equal to the second derivative with respect to x plus. The second derivative

with respect to y plus the second derivative with respect to z that is what Del squared

is, so I am going to separate out these 2 pieces. And keep this separate, so del squared

E del x squared plus del squared E del y squared plus del squared E del z squared minus 1 over

c squared del squared E del t squared is equal to 0. I just put brackets this 2 equation

are identical, because I just written out the del squared collected 2 terms. And put

the third term with the time derivative now I am going to make a guess I am saying I am

having a long tube. So, whatever shape I have in x and that shape

remains what it is as I go down in z. So, if I cut here I will still see the same shape

and if i go further and i will see the same shape. So, I guess that the electric field

has a dependence on x and y which is independent of how it depends on z and t. So, I write

a electric field as some vector which depends on x and y alone times e to the j omega t

minus kz. This is perfectly reasonable I do this because I can see that time and in z

my structure is symmetric if I shift in z problem looks the same. So, I look for sins

and cosines in z by shift in time the problem looks the same. So, I can looks for sins and

cosines in t, but I cannot shift in x and y, because there where pipe.

So, that problem is more complicated if I substitute this in here and I will call this

E perp I can write. This as Del squared xy acting on E perp multiply by the e to the

j omega t minus kz plus the Del del z squared will act on k kz. So, I will get a minus k

squared plus omega squared over c squared e perp e to the j omega t minus kz is equal

to 0. So, all I have done is I substituted this form into this equation this part. I

do not know about is going to do is just going to act on this unknown function. But this

part I know what is going to do because i know the form of the dependence of time. And

the dependence on z, so I pulled it out let me get rid of the exponential, because it

is common, so I remove it. Now, if I want to compare this problem with

the plane wave problem I would need to get rid of this piece without this piece this

is nothing. But my 1 dimensional wave equation this piece is what is going to complicate

my life. So, I look for solutions where this piece goes away. So, I try to find solutions

where the Del squared xy acting on this amplitude

which depends on only xy is equal to 0 if I could find it. Then the rest of it is done

this is 1 dimensional wave equation. So, it is my plane wave bottled into a pipe and packaged.

And then send now the question is how do I solve this problem? I have gone from one problem

to another. But the second problem does not look any easier then the original problem.

So, I want Del squared Del x squared of my E perp plus Del squared Del y squared of E

perp is equal to 0. And E perp cross the normal to the surface is equal to 0 on boundary,

because the tangential components must be 0. Now, what I am going to do is I am going

to look at this and say this does not depends on time at all. So, I will guess E perp is

a vector is equal to gradient of some scalar after all it looks like electro statics to

me. So, why not try it even this looks like electrostatics its say there is no tangential

electric field,, so the wall is a eqi potential. So, let me put back into this what do I get

I get del squared del x squared plus del squared del y squared acting on minus del pi del x

x hat minus del pi del y y hat is equal to 0. And in addition pi equals constant on surface,

because I need tangential components to go to 0. So, pi is constant,, so tangential component

is also 0. Now, because these are all derivatives without any coefficients I can always commute

them I can pull this Del del x outside and I can put these inside.

So, I can write this as x hat del del x plus y hat del del y acting on del squared del

x squared plus del squared del y squared of pi, because after all second partial derivative

is commute. So, it does not matter in which order I do it del y del x del del del y del

x or del del x del del y. So, the order does not matter I will do this operation. And I

will do this operation after I do this operation. But, when you look at this equation what does

it say it says minus gradient of del squared pi equals 0 which can be easily satisfied

its if del squared pi is equal to 0. So, I am really looking for solving this problem

I am looking for something very simple I am saying. That the guess that the electric field

looks like this some function of x y times E to the j omega t minus kz. And this function

of xy is derived from a potential and this potential satisfies Laplaces equations

let us look for an example. And see whether all of this mix in or not.

I will start with the central conductor and a metallic pipe the outside I am going to

hold that ground inside such sum voltage v. And there is dielectric now really I should

say I am holding it around voltage v its going to be carrier wave, which mean that the voltage

is not constant the voltage is function of z. But when I look for the solution of this

problem I am looking for del squared pi is equal to 0 pi equal to 0 on outer wall pi

equals v on inner wall this is a well known problem. We have already done it this is nothing,

but what we did for calculating capacitance of 2 cylinders. So, you can easily find the

solution and you know that there is radically symmetric Er. This electric field Er will

satisfy del squared pi is equal to 0. There is no tangential electric field on the outside

surface there is no tangential field on the inside surface. So, its satisfies all the

conditions that we want and therefore, del squared xy of e perp is 0. And the boundary

conditions are satisfied what does that it means for that particular form we are solving

only this equation.

Now; that means, my solutions is going to be look like this the electric field which

is the function of x y z.

And t it really an Er along r direction that Er, we can work out is going to like 1 over

r. So, you can say E not over r e to the j omega t minus kz what will the corresponding

H look like? This will be the curl of E. So, when you look for the curl of E is going to

be take the z derivative of Er. That will be in the theta direction H of x y z t will

again look like some H not over r in the theta direction e to the j omega t minus kz.

And when we put this into wave equation you get this solution which means omega is equal

to plus or minus kc. Now, these are very special waves these are not the waves that are used

for taking high energy radar signals. They have quite a few nice properties for one thing

the line that connect omega and k. The curve that connects omega and k, if you plot it

you find that it is a straight line.

Now, this is very important, because if you look at what happens?

If I have a circuit and I have a switch and a closed switch, when I close this switch

current will start to flow, now the speed with which the signal that the switch is closed

goes through. These circuits depends on how well the signals propagate through this wires

if the signal propagate at different velocities at different frequencies. Then what will happen

is out here in time the signal is switched just closed and instantly the signal came

on. And continue, but out here it may very well be that the signal will look like this

that is to say the fact that. The switch closed was not very sharp start in the current starts

gradually there is a rise time to this signal. And this rise time due to the signal comes,

because the wire is not carrying all frequency with the same velocity. But this particular

solution we have with a special solution it does. In fact, care carry all a frequency

that the same velocity, because the velocity is nothing but omega over k which is equal

to c, so all frequency travel together. So, if I take the Laplace or Fourier transform

of this signal its a spectrum every part of the spectrum travels together again take the

inverse transform here. And I will get back the same shape it would not be 1 1 frequency

is delayed with respect to the other which is the main cause of this kinds of effects.

So, that is one important advantage of such waves and these waves are called TEM waves

transverse electro magnetic waves. And they are the waves that live in what we call transmission

lines. Now, in a certain sense transmission lines has come to rule electrical engineering

no mater which branch of electrical engineering you are in that is. Because the state of the

art has kept progressing till; however, fast or, however slow your circuits are they are

pushing the limit. And the limits are always the limits of signal propagation through circuits.

So, you can see this happening through the different technologies that are happening

in different branches of electrical engineering for instance naturally in communications.

Transmission lines are required waveguides and transmission lines are automatically required,

but you look at for example.

A PC main mother board now that does not look as not communications after all what about

it well the size of lines on a PC mother board a few centimeters. And the speed of the clock

on the mother board which are 100s of mega hertz combine together. So, that in fact,

signal delay will becomes crucial. So, once again you find the transmission lines are

crucial you do not take proper care of delays you do not properly understand. The transmission

line, you can not design a good motherboard whatever in IC chip well these distances of

lines are now in tens of microns to 100s of microns.

But the speeds are much higher, because the speeds are much higher once again signal propagation

delays are important. And you have transmission lines once again, so you comes lower in frequency

and. So, you come to power lines. Now, you are talking about 50 60 hertz, but your power

lines are very long your power line can be crossing a country. And once its starts getting

approaching a large fraction of a 1000 kilometers once again you are a transmission line. So,

the theory of transmission lines and more generally the theory of wave guide have come

to dominate electrical engineering no matter which branch you are in.

And it is the same theory, the theory cannot change, because we are talking about power

lines as suppose to communications in all these cases what is important is that you

are able to separate the del squared of Ex and Ey. And the solution along the z which

is Del squared Del z squared minus 1 over c squared del square del t squared of the

behavior in t and z. So, I gave 1 example of this which

was cylindrical 2 wired guide that is what you call a bmc cable it is also found in the

tv coaxial cable. And all of those are machine to great precision, so that you can carry

the signals up to very high frequencies. But since we are talking about low frequency effects

we can also talk about power lines.

Because you can consider 2 wires one of which is at 1 voltage and the other is at the, another.

So, you have current flowing into this and coming out of this wire these are the written

path of this current. Then we are solving for xy electric fields

by solving this capacitance problem is its solvable problem. In fact, there are exact

solutions available and if you solve this problem. And substituted back into this equation

you got the transmission line that is used by power lines. And this is nothing, but the

electro magnetic wave that travels through the 100s. of kilometers in which a power is

transmitted. So, the power is actually going into the board. But, electro static and magneto

static fields are set up due to the charges and the currents that get established on this,

wires. So, it is a important thing to realize that

transmission line are a very unifying idea. And they are in fact, like you might say the

final step in a basic electromagnetic course. You have learned about static field you have

learned about magneto static fields. We learned about motional emf we learned about waves.

And when we went to waves it was like when we went to a new subjects. But actually now,

we come all the way back we have talking about using those waves inside circuits. We are

talking about power lines carrying power we are talking about Ethernet cable carrying

signals. And those circuit elements are in fact, waves again and perhaps most important

part of it is to solve for this waves. You need electrostatics you are not using wave

theory wave theory is the simple part you have to do electro statics.

Now, you are doing PC mother board; you would have a high permittivity epsilon of may be

10 12 high permittivity material dielectric on which you have thin copper strips. The

bottom part of this plate is actually fully copper

and it is connected to the ground. This is what calls a 2 layer boat and of course, a

standard PC mother board will not be 2 layers. It will 2 layer or 6 layer or higher, but

this is the simplest way of looking at it. So, what happens is if you look at this structure?

And look at it from side waves you have your dielectric

at the bottom you have copper. And this copper is grounded at the top you have more copper

current signal flow in into this copper strips. That is they are flowing this way that is

in to the board in this picture when this when charges get built up on this strip you

get capacitance. You have to solve this problem this problem would be the problem of having

an air dielectric. And epsilon greater than much epsilon naught

with copper strip in the middle this problem corresponds to solving. This having solved

it and actually there are some problems I would not go into them. So, it is only a imperfect

solution you can make having solves them we have then left with the transmission line

the transmission carries signals along. This, wire at essentially the speed of light actually

half the speed of light approximately similarly, in an IC chip I mean. The same ideas go whether

it is in a PCB and an IC chip are even in a microstrip antenna. Now, if you are done

your transmission line course are even, if you have in when you get to it the language

will be very different. You will not see the wave theory at all in fact, you will see a

distributed rlc network.

You will told that the transmission line can be viewed as a 2 port network

and you can put can put an equivalent circuit. This distance would be dz this would be c

over 2 c over 2 dz. And this is Ldz and you will be told that this represents the transmission

lines an idea transmission for a short distance dz. And then you combine many many such section

and you get the behavior of a transmission line which does not look like very much like.

This equation at all this equation came from studying maxwells equations where as this

is more of a equivalent circuit. So, where does this picture fit in? With this picture

well the way to look at it is as follows imagine that.

We have a parallel plate capacitor which is very long this direction is z and this direction

the direction between the plates is x. And we do not care too much what is happening

in y. So, we have again the possibility of tem wave, because you can solve for capacitance

of the arrangement. So, we will have electric fields and then the electric fields will change

direction and that is, what is our wave. The wave is going in this z direction now; I want

to convert from electric and magnetic field to voltages and current, because that is what

circuits know and that is what is the equation? The equation has do with the inductors and

capacitors. Well, the idea is we have solved for a potential we looked for E equals minus

grade pi. So, therefore, we can talk about the voltage across these plates.

We can calculate integral E dot dl from 0.1 to 0.2 we can also talk about E dot dl from

0.3 to 0.4 and let say that this distance is dz. So, in that case I can talk about E

dot dl from 3 2 4 and E dot dl from 1 to 2. So, I can do integral 3 2 4 E dot dl minus

integral 1 to 2 E dot dl which is nothing but loop integral E dot dl, because electric

field is up. So, this 2 components sections do not do anything electric field is orthogonal

to dl, what is that? That is nothing but surface integral curl of E dot ds which is apply Faradays

law minus del B del t dot ds. I will pull the del del t out. It is minus del del t of

surface integral B dot ds. But we know that surface integral B dot ds is nothing but flux

and flux is li. We can write this as minus del del t of LI let see what we have written

this L or this flux is the flux between of region a of dzy.

So, this inductance is Ldz and this difference is voltage at z plus dz minus voltage at z

and I am going to take that dz out. And bring it this side divided by dz is equal to del

del t of LI this is nothing but the z derivative of voltage which gives as a circuit equation.

The circuit equation is del v del z is equal to minus L time del I del t. Similarly, you

get another equation, the other equation will use Amperes law.

And it will give you del I del z is equal to minus C del v del t and these 2 equation

together will give you the transmission line equations. The lesson to be learned here is

all the work that you have done in electromagnetic theory statics motional emf waves as finally,

reached here. It allows as to define a wave that is bottled into a pipe. And that wave

that is bottled into a pipe a useful variant of that wave is what we call a tem wave. And

that tem wave can be modeled by circuit concept you can talk about inductance per unit length.

And correspondingly we can talk about capacitance per unit length. And you can instead of talking

about electric and magnetic fields talk about voltages. And currents when you do that, this

is nothing but the theory of transmission lines. And the theory of transmission lines

is the practical aspects of electromagnetic theory.

The Description of Lecture-41-Transmission Lines